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what is the equation of the line that is perpendicular to y=2x-8 and goes through the points (2,5)?

Respuesta :

nobillionaireNobley
For perpendicular lines, m2 = -1/m1

y = 2x - 8 has a slope of 2, so the perpendicular line will have a slope of -1/2

Required equation is y - 5 = -1/2 (x - 2)
y = -1/2 x + 1 + 5
y = -1/2 x + 6

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