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Forty discrete math students are to be divided into eight discussion groups, each consisting of five students. In how many ways can this be done?

Respuesta :

samuelonum1

Answer:

76904685 ways

Step-by-step explanation:

Given data

the number of students n=40

the number of groups r= 8

We are going to use the combination approach to solve the problem

nCr= n!/r!(n-r)!

substituting into the expression for the number of ways we have

40C8= 40!/8!(40-8)!

nCr= 40!/8!(32)!

nCr= 40!/8!(32)!

nCr= 40*39*38*37*36*35*34*33*32!/8!(32)!

nCr= 40*39*38*37*36*35*34*33*/8!

nCr= 40*39*38*37*36*35*34*33*/8*7*6*5*4*3*2

nCr= 3100796899200/40320

nCr=76904685 ways

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