Respuesta :
Answer:
The fractional saturation for hemoglobin is 0.86
Explanation:
The fractional saturation for hemoglobin can be calculated using the formula
[tex]Y_{O_{2} } = \frac{(P_{O_{2} })^{h} } {(P_{50})^{h} + (P_{O_{2} })^{h} }[/tex]
Where [tex]Y_{O_{2} } \\[/tex] is the fractional oxygen saturation
[tex]{P_{O_{2} }[/tex] is the partial pressure of oxygen
[tex]P_{50}[/tex] is the partial pressure when 50% hemoglobin is saturated with oxygen
and h is the Hill coefficient
From the question,
[tex]{P_{O_{2} }[/tex] = 40 mm Hg
[tex]P_{50}[/tex] = 22 mm Hg
h = 3
Putting these values into the equation, we get
[tex]Y_{O_{2} } = \frac{(P_{O_{2} })^{h} } {(P_{50})^{h} + (P_{O_{2} })^{h} }[/tex]
[tex]Y_{O_{2} } = \frac{40^{3} }{22^{3} + 40^{3} }[/tex]
[tex]Y_{O_{2} } = \frac{64000 }{10648 + 64000 }[/tex]
[tex]Y_{O_{2} } = \frac{64000 }{74648 }[/tex]
[tex]Y_{O_{2} } = 0.86[/tex]
Hence, the fractional saturation for hemoglobin is 0.86.
