Respuesta :
Answer:
1). A. Add/subtract a quantity to/from only one side
2) B. No
Step-by-step explanation:
Given equation A
5x-2+x = x-4
Given equation B
5x+x = x-4
We can see that the difference between equation A and B is the 2 that subtracted from the left hand sides of the equation A. All other functions and constants remains the same.
For us to be able to get equation B from A, we need to simply add 2 to the left hand side of equation A to cancel out the -2 that is there as shown:
From equation A:
[tex]5x-2+x = x-4[/tex]
Add 2 to the left hand side of the equation
[tex]5x-2+x+2 = x-4[/tex]
Simplify
[tex]5x-2+2+x = x-4\\5x+0+x = x-4\\5x+x = x-4[/tex]
We can see that the resulting function gives the equation B
Hence the option B is correct i.e Add/subtract a quantity to/from only one side
Let us find the solution to equation A and B
For equation A:
[tex]5x-2+x = x-4\\5x+x-2 = x-4\\6x-2 = x-4\\6x-x = -4+2\\5x = -2\\x = -2/5[/tex]
For equation B:
[tex]5x+x = x-4\\5x+x-x = 4\\6x-x = 4\\5x = 4\\x= 4/5[/tex]
Since we got different solution for x in both equation, hence both equation are not equivalent.
Answer:
Add/subtract the same quantity to/from both sides .... and yes
Step-by-step explanation:
got the answer from khan.