Complete question
The complete question is shown on the first uploaded image
Answer:
a
[tex]y' = 0.85 [/tex]
b
[tex]P(J) = 0.27 [/tex]
c
[tex]P(R) = 0.0144 [/tex]
d
[tex]P(R') = 0.7744 [/tex]
e
[tex]P(Q) =0.2256 [/tex]
Step-by-step explanation:
From the question we are told that
The proportion of M & M's that is brown is b = 0.12
The proportion of M & M's that is yellow is y = 0.15
The proportion of M & M's that is red is r = 0.12
The proportion of M & M's that is blue is b = 0.23
The proportion of M & M's that is orange is o = 0.23
The proportion of M & M's that is green is g = 0.15
Generally the probability that a random selected M&M is not yellow is
[tex]y' = 1-y[/tex]
=> [tex]y' = 1-0.15[/tex]
=> [tex]y' = 0.85 [/tex]
Generally the probability that a randomly selected peanut M&M isgreen or red is mathematically represented as
[tex]P(J) = g + r [/tex]
=> [tex]P(J) = 0.15 + 0.12 [/tex]
=> [tex]P(J) = 0.27 [/tex]
Generally the probability that two randomly selected peanut M&M’s are both red is mathematically represented as
[tex]P(R) = r^2[/tex]
=> [tex]P(R) = 0.12^2[/tex]
=> [tex]P(R) = 0.0144 [/tex]
Generally if two two peanut M&M’s are selected the probability that neither of them are red is mathematically represented as
[tex]P(R') = (1 -r)^2[/tex]
=> [tex]P(R') = (1 - 0.12)^2[/tex]
=> [tex]P(R') = 0.7744 [/tex]
Generally if two two peanut M&M’s are selected the probability that at least one of them is red is mathematically represented as
[tex]P(Q) = 1- P(R')[/tex]
=> [tex]P(Q) = 1- 0.7744 [/tex]
=> [tex]P(Q) =0.2256 [/tex]
