Answer:
A=750 +75*t
B=900 +25*t
There would be 975 students in each high school in year 3 when they are expected to have the same number of students.
Step-by-step explanation:
You know that High School A currently has 750 students and is projected to grow by 75 students each year. With A being the number of students in High School A in t years, this number will be the number of students it has initially added to the number of students who have joined after t years. This is represented by:
A=750 +75*t
You know that High School B currently has 900 students and is projected to grow by 25 students each year. With B being the number of students in High School B in t years, this number will be the number of students it has initially added to the number of students who have joined after t years. This is represented by:
B=900 +25*t
You want to determine how many students there would be in each high school in the year that they are projected to have the same number of students. That is, in year t the number of students is the same, so
A = B
750 +75*t=900 + 25*t
Solving:
75*t -25*t= 900 - 750
50*t= 150
[tex]t=\frac{150}{50}[/tex]
t=3
This indicates that in year 3 both High Schools are projected to have the same number of students. To get that amount, you simply replace this value in the expressions:
A=750 +75*t= 750 +75*3= 975
B=900 + 25*t=900 + 25*3= 975
There would be 975 students in each high school in year 3 when they are expected to have the same number of students.
Answer: REAL ANSWER
A= 75t +750
B=25t +900
Answer: 975 students
