Answer:
40.0⁰
Explanation:
The formula for calculating the magnetic flux is expressed as:
[tex]\phi = BAcos\theta[/tex] where:
[tex]\phi[/tex] is the magnetic flux
B is the magnetic field
A is the cross sectional area
[tex]\theta[/tex] is the angle that the normal to the plane of the loop make with the direction of the magnetic field.
Given
A = 0.250m²
B = 0.020T
[tex]\phi[/tex] = 3.83 × 10⁻³T· m²
3.83 × 10⁻³ = 0.020*0.250cosθ
3.83 × 10⁻³ = 0.005cosθ
cosθ = 0.00383/0.005
cosθ = 0.766
θ = cos⁻¹0.766
θ = 40.0⁰
Hence the angle normal to the plane of the loop make with the direction of the magnetic field is 40.0⁰
