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Container A and container B have leaks. Container A has 800ml of water, and is leaking 6 ml per minute. Container B has1000 ml, and is leaking 10 ml per minute. How many minutes, m, will it take for the two containers to have the same amount of water?

Respuesta :

TheMansTired

Answer:

50 minutes

Step-by-step explanation:

First set up an inequality to find you answer like

800 - 6x = 1000 - 10x

then subtract 800 from both sides leaving you with

-6x = 200 - 10 x

Then add 10 x to both sides giving you

4x = 200

The simplify from here by dividing 200 by 4

200/4 = 50 giving you your answer

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