Answer:
The approximate probability that the total weight of the passengers exceeds 4432 pounds is 0.2709
Step-by-step explanation:
[tex]\mu = 192[/tex]
[tex]\sigma = 31[/tex]
No. of passengers = n = 21
We are supposed to find the approximate probability that the total weight of the passengers exceeds 4432 pounds
[tex]x = \frac{4432}{21} \sim 211[/tex]
[tex]Z=\frac{x-\mu}{\sigma}\\Z=\frac{211-192}{31}[/tex]
Z=0.612
refer z table
P(Z<211)=0.7291
P(Z>211)=P(Z>4432)=1-0.7291=0.2709
Hence the approximate probability that the total weight of the passengers exceeds 4432 pounds is 0.2709