Answer:
[tex] x = \dfrac{1}{6} + \dfrac{i\sqrt{47}}{6} [/tex] or [tex] x = \dfrac{1}{6} - \dfrac{i\sqrt{47}}{6} [/tex]
Step-by-step explanation:
Use the quadratic formula.
[tex] x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a} [/tex]
[tex] x = \dfrac{-(-1) \pm \sqrt{(-1)^2 - 4(3)(4)}}{2(3)} [/tex]
[tex] x = \dfrac{1 \pm \sqrt{1 - 48}}{6} [/tex]
[tex] x = \dfrac{1 \pm \sqrt{-47}}{6} [/tex]
[tex] x = \dfrac{1}{6} \pm \dfrac{i\sqrt{47}}{6} [/tex]
[tex] x = \dfrac{1}{6} + \dfrac{i\sqrt{47}}{6} [/tex] or [tex] x = \dfrac{1}{6} - \dfrac{i\sqrt{47}}{6} [/tex]
