The total distance traveled by the dog is 100 m and the displacement of the dog is 58.31 m.
The given parameters;
- Initial position of the dog, 40 m west
- Second position of the dog, 10 m east
- Final position of the dog, = 50 south
The displacement of the dog is the change in its initial position and the final position.
The resultant of the dogs position in x-direction: = 40 m - 10 m = 30 m
The resultant of the dogs position in y-direction: 50 m
The magnitude of the displacement;
R² = 30² + 50²
R² = 3400
R = √3400
R = 58.3 m
The distance covered by the dog is the sum of all the positions of the dog.
Distance = 40 m + 10 m + 50 m
Distance = 100 m.
Thus, the total distance traveled by the dog is 100 m and the displacement of the dog is 58.31 m.
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