[tex]h(x) = x + 1[/tex]
[tex]k(x) = x - 2[/tex]
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[tex](h + k)(x) = h(x) + k(x)[/tex]
[tex](h + k)(x) = (x + 1) + (x - 2) \\ [/tex]
[tex](h + k)(x) = x + 1 + x - 2[/tex]
[tex](h + k)(x) = 2x - 1[/tex]
[tex](h + k)(2) = 2(2) - 1[/tex]
[tex](h + k)(2) = 4 - 1[/tex]
[tex](h + k)(2) = 3[/tex]
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And we're done.....♥️♥️♥️♥️♥️
