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2. The allele for webbed hands (W) is dominant to normal hands (w). Complete a Punnett square
to predict the offspring should a heterozygous male cross with a heterozygous female.
a) Determine the genotype of each parent:
(parent one)
(parent two)
b) Complete the punnett square
c) Complete the ratios of the genetic cross:
d) What is the percentage that the offspring will have webbed hands?
e) What is the percentage that the offspring will have normal hands?

Respuesta :

usernamee16
a. both parent would be Ww
b. see picture (for the top left it would be Ww not wW)
c. 2 Ww, 1 WW, 3 ww (i think i’m not sure how to do ratio)
d. 75%?
e. 25%
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shivjimishraVT

When a heterozygous male (Ww) crosses with a heterozygous female (Ww), the resulting offsprings possess genotypes WW, Ww, Ww, and ww.

What do you mean by Genotype?

Genotypes may be defined as the ultimate combinations of the alleles of those genes which are selected for studies.

  • The genotypes of both parents are heterozygous i.e. Ww.
  • The ratio of the complete genetic cross is 3:1.
  • The percentage that the offspring will have webbed hands is 75%. (WW, Ww, Ww)
  • The percentage that the offspring will have normal hands is 25% (ww).

The Punnett square is attached below:

Therefore, it is well described above.

To learn more about Genetic crosses, refer to the link:

https://brainly.com/question/21011399

#SPJ2

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