Given the function g(x)=-x^2+6x+12g(x)=−x
2
+6x+12, determine the average rate of change of the function over the interval -3\le x \le 5−3≤x≤5.

Respuesta :

Answer:

4

Step-by-step explanation:

edge

The average rate of the function is 4.

What is average rate of function?

The average rate of change of a function f(x) over an interval [a, b] is defined as the ratio of "change in the function values" to the "change in the endpoints of the interval". i.e., the average rate of change can be calculated using [f(b) - f(a)] / (b - a). In other words, the average rate of change (which is denoted by A(x)) is the "ratio of change in outputs to change in inputs". i.e.,

A(x) = (change in outputs) / (change in inputs)

= Δy / Δx

= [f(b) - f(a)] / (b - a)

given function:

f(x) = -x² + 6x + 12

Now,

let a= -3, b = 5

and, f(b)= -(5*5) + 6*5 + 12

 =-25+ 30 +12

 = 17

f(a) = -(- 3 * (-3))+6(-3) +12

  = -9-18+12

  = -15

Now,

f(b)- f(a) / (b-a)

=17 -(-15))/5-(-3)

=32/ 8

=4

Learn more about rate of change here:

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