Respuesta :
11.9 grams of CaCl₂ is required to make 1 Liter of 0.1M solution.
Calculating the amount of CaCl₂ required:
We first need to calculate the molecular weight of calcium chloride CaCl₂.
The atomic weight of Ca = 40.01
and the atomic weight of Cl₂ = 2×35.45 = 70.90
So, the molecular weight of CaCl₂ = 40.01 + 70.90 = 110.91
This means that 110.91 g of CaCl₂ mixed with enough water will produce 1Liter of 1M solution.
Now, to calculate the amount of CaCl₂ required to make 1 Liter of 0.1M solution we use:
grams of chemical = (molarity of solution in mole/liter) x (MW of chemical in g/mole) x (ml of solution) ÷ 1000 ml/liter
= 0.1 × 110.91 × 1000 ÷ 1000
= 11.09 grams
So, 11.09 grams of CaCl₂ will be used.
Learn more about molarity:
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