Answer:
84 J
Explanation:
Work by mover:
W = Fd
W = 496 J (2.1 m)
W = 1042 J
Work by dolly and ramp:
W = Fd
W = (mg)d
W = 115 kg (9.8 m/s/s) (0.85 m)
W = 958 J
1042 J - 958 J
= 84 J
The amount of work spent in overcoming friction is 83.65 J.
From the question,
The amount of work spent in overcoming friction = work done by the mover-potential energy of the refrigerator.
This is expressed mathematically as,
W' = Fd-mgh................... Equation 1
Where W' = work spent against friction, F = force applied, d = distance, m = mass of the refrigerator, g = acceleration due to gravity, h = height.
From the question,
Given: F = 496 N, d = 2.10 m, m = 115 kg, h = 0.85 m
Constant: g = 9.8 m/s².
Substitute these values into equation 1
W' = 496(2.1)-(115×9.8×0.85)
W' = 1041.6-957.95
W' = 83.65 J.
Hence, the amount of work spent in overcoming friction is 83.65 J
Learn more about friction here: https://brainly.com/question/13683196
