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Consider this polynomial equation.
6(x - 3)(x2 + 4)(x + 1) = 0
Use the equation to complete this statement.
The equation has
solutions. Its real solutions are a

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Answer:

This equation has 4 solutions, its real solutions are x = -1 and 3

Step-by-step explanation:

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The equation has 4 solutions and its real solutions are 3, -1.

The given polynomial equation is 6(x - 3)(x² + 4)(x + 1) = 0.

What does a real solution mean in math?

A real solution in algebra is simply a solution to an equation that is a real number.

Now, 6(x - 3)(x² + 4)(x + 1) = 0

⇒(x - 3)(x² + 4)(x + 1) = 0

⇒(x - 3)=0, (x² + 4)=0 and (x + 1) = 0

⇒x=3, -1 and ±√-4.

Therefore, the equation has 4 solutions and its real solutions are 3, -1.

To learn more about the polynomial equation visit:

https://brainly.com/question/20630027.

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