Answer:
The acceleration of the ball from 0.5 to 0.7 seconds is 10 m/s²
Explanation:
The data from the given velocity-time graph are as follows;
Velocity (meters per second) [tex]{}[/tex] Time (seconds)
0 [tex]{}[/tex] 0.4
0.5 [tex]{}[/tex] 0.45
1. [tex]{}[/tex] 0.5
1.5 [tex]{}[/tex] 0.55
2.2 [tex]{}[/tex] 0.6
2.5 [tex]{}[/tex] 0.65
3.0 [tex]{}[/tex] 0.7
3.5 [tex]{}[/tex] 0.75
4.0 [tex]{}[/tex] 0.8
4.5 [tex]{}[/tex] 0.85
Therefore, the average acceleration of the ball from 0.7 to 0.7 seconds is given as follows;
Acceleration = (Change in velocity)/(Related change in time)
Acceleration = (3.0 - 1)m/s/(0.7 - 0.5)s = 2/0.2 m/s² = 10 m/s²
The acceleration of the ball from 0.5 to 0.7 seconds = 10 m/s².
