Answer:
Explanation:
Time of fall be t
Considering downward fall
h = 1/2 g t²
.8 = .5 x 9.8 t²
t² = .16
t = .4 s
Marble lands at .6 m away from the base
If u be its horizontal initial velocity
u x .4 = .6
u = 1.5 m /s .
The initial velocity of the marble will be "1.5 m/s".
According to the question,
Height of table, h = 0.8 m
Marble lands = 0.6 m
Acceleration due to gravity, g = 9.8
Let,
The time of fall be "t".
We know the relation,
→ h = [tex]\frac{1}{2} gt^2[/tex]
By substituting the values, we get
0.8 = 0.5 × 9.8 t²
t² = 0.16
t = √0.16
= 0.4 s
hence,
The horizontal initial velocity will be:
→ u × 0.4 = 0.6
u = [tex]\frac{0.6}{0.4}[/tex]
= 1.5 m/s
Thus the answer above is appropriate.
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