Respuesta :
Using quadratic formula, the possible values of x lies in [0, 5.728].
What is a quadratic formula?
The quadratic formula is a formula that provides the solution to a quadratic equation.
[tex]x = \frac{ -b \pm \sqrt{b^2 - 4ac}}{2a} \\\\when\ ax^2 + bx + c = 0\\a, b, c = constants, \\where\ a != 0\\x= the\ unknown[/tex]
The equation in the given question is-
[tex](x+3)(x) < =50\\\\x^{2} +3x-50 < =0\\\\x^{2} +3x-50=0\\\\x = \frac{-3 +\sqrt{9+4*50} }{2} ,\frac{-3 -\sqrt{9+4*50} }{2}\\\\x = \frac{-3 +\sqrt{209} }{2} ,\frac{-3 -\sqrt{209} }{2}\\\\\\x = -8.728, 5.728\\\\x =[-8.728, 5.728][/tex]
But, x cannot be negative so x lies in [0, 5.728].
Learn more about quadratic formula here
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