[tex] ({v})^{2} - ({v(0)})^{2} = 2 \times a \times ∆x[/tex]
[tex]v = the \: \: speed \: \: before \: \: reaching \: \: ground \\ [/tex]
[tex]v(0) = the \: \: speed \: \: in \: \: the \: \: rest \: \: which \: \: is \: \: zero \\ [/tex]
[tex]a = Acceleration \: = \: Gravity \: \: acceleration = 10 \\ [/tex]
[tex]∆x = covered \: \: distance[/tex]
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[tex] {v}^{2} - ({0})^{2} = 2 \times 10 \times 13 [/tex]
[tex] {v}^{2} = 2 \times 2 \times 5 \times 13 [/tex]
[tex]v = \sqrt{ {2}^{2} \times 65 } [/tex]
[tex]v = 2 \sqrt{65} \: \: \frac{m}{s} [/tex]
Done.....♥️♥️♥️♥️♥️
