Select all the equations where z=5z=5z, equals, 5 is a solution.

Choose 3 answers:

Choose 3 answers:


(Choice A)

A

8=z+38=z+38, equals, z, plus, 3


(Choice B)

B

z-1=6z−1=6z, minus, 1, equals, 6


(Choice C)

C

20=40\div{z}20=40÷z20, equals, 40, divided by, z


(Choice D)

D

12z=6012z=6012, z, equals, 60


(Choice E)

E

12+z=1712+z=17

Respuesta :

Answer:

A, D and E

Step-by-step explanation:

A.

[tex]8 = z + 3[/tex]

Subtract 3 from both sides

[tex]8 -3 = z + 3-3[/tex]

[tex]5 = z[/tex]

[tex]z = 5[/tex]

B.

[tex]z - 1 = 6[/tex]

Add 1 to both sides

[tex]z - 1+1 = 6 + 1[/tex]

[tex]z = 7[/tex]

C.

[tex]20 = \frac{40}{z}[/tex]

Multiply through by z

[tex]z * 20 = \frac{40}{z} * z[/tex]

[tex]20z = 40[/tex]

Divide through by 20

[tex]\frac{20z}{20} = \frac{40}{20}[/tex]

[tex]z = 2[/tex]

D.

[tex]12z = 60[/tex]

Divide through by 12

[tex]z = 60/12[/tex]

[tex]z = 5[/tex]

E

[tex]12 + z = 17[/tex]

Subtract 12 from both sides

[tex]-12 + 12 + z = 17 - 12[/tex]

[tex]z = 5[/tex]

Hence:

A, D and E answers the question