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Train A is traveling at 70 mph to a destination 200 miles away. Train B will leave 20 minutes after train A. Train B will leave from Train A's destination and will head in Train A's direction. If Train B will be going at a speed 32 of Train A's, how long after Train A left will it take before Train B arrives at Train A's starting point? Round your answer to the nearest tenth of an hour

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Answer:

The answer is "2.2 h"

Step-by-step explanation:

Speed of Train B:

[tex]= \frac{3}{2} \times 70 \ mph \\\\= 105 \ mph[/tex]

Train B is then moving on:

[tex]= \frac{200 \ miles}{ 105 \ mph} \\\\= 1.905 \ h\\[/tex]

Then it takes Train A to the left:

[tex]\to 1.905\ h + 20 \ min \\\\= 1.905 \ h +0.333 \ h \\\\= 2.238 \ h[/tex]

To get train B to the reference point of train A = 2.2 h    

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