Answer:
Tech B is correct.
Explanation:
The voltage drop between the two terminals of a circuit is the measurement of the potential difference between the two terminals.
If [tex]v_1[/tex] and [tex]v_2[/tex] ( assuming [tex]v_1 > v_2[/tex]) are potentials at terminal 1 and terminal 2 of the given open circuit.
According to A, the measurement of the potential drop is 12 volts, i.e
The measurement of potential difference [tex]=v_1 -v_2[/tex]
= 12 volts which is correct.
But according to B, a measurement of 12 volts means there are 12 volts on each side of the switch ([tex]v_1= 12[/tex] volts and [tex]v_2=12[/tex] volts), i.e
According to the claim of B, the potential difference (or drop) across the terminals is
[tex]v_1-v_2= 12-12=0[/tex] but the measured potential drop is 12 volts, so B is wrong.
Hence, Tech B is correct.