Answer:
57.9 grams .
Explanation:
Ca₃(PO₄)₂ + 3H₂SO₄ → 3CaSO₄ + 2H₃PO₄
1 mole 3 moles 2 moles
149 g of Ca₃(PO₄)₂ = 149 / 310 = .48 moles
86.9 g of H₂SO₄ = 86.9 / 98 = .8867 moles
Here H₂SO₄ is the limiting reagent .
.8867 / 3 = .2955
.2955 moles of Ca₃(PO₄)₂ reacts with .8867 mole of H₂SO₄ to give
2 x .2955 moles of H₃PO₄
H₃PO₄ produced = 2 x .2955 moles
= .591 moles
= .591 x 98 = 57.9 grams .
