Answer:
The coordinates of endpoint S are [tex]S(x,y) = (8,-18)[/tex].
Step-by-step explanation:
Let [tex]T(x, y) = (0, 6)[/tex] and [tex]M(x,y) = (4,-6)[/tex], which is the midpoint of line segment ST. From Linear Algebra we get that midpoint is the following vector sum of endpoints S and T. That is:
[tex]M(x,y) = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot T(x,y)[/tex] (Eq. 1)
Now clear S in the previous expression:
[tex]S(x,y) = 2\cdot M(x,y) - T(x,y)[/tex] (Eq. 1b)
Then, the coordinates of point S are:
[tex]S(x,y) = 2\cdot (4,-6) - (0,6)[/tex]
[tex]S(x,y) = (8, -18)[/tex]
The coordinates of endpoint S are [tex]S(x,y) = (8,-18)[/tex].
