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an object is traveling with a velocity of 3.05 m/s. the object then accelerates at 2.82 m/s^2 over a displacement of 18.4m. what is the final velocity? answer choices - 2.82m/s, 113.1m/s, 54.9m/s, 10.6m/s

Respuesta :

Lanuel

Answer:

Final velocity, V = 10.6 m/s

Explanation:

Given the following data;

Initial velocity, U = 3.05m/s

Acceleration, a = 2.82m/s²

Displacement, S = 18.4m

To find the final velocity of the object, we would use the third equation of motion;

[tex] V^{2} = U^{2} + 2aS [/tex]

Where;

  • V represents the final velocity measured in meter per seconds.
  • U represents the initial velocity measured in meter per seconds.
  • a represents acceleration measured in meters per seconds square.
  • S represents the displacement measured in meters.

Substituting the values into the equation, we have;

[tex] V^{2} = 3.05^{2} + 2*2.82*18.4[/tex]

[tex] V^{2} = 9.3025 + 103.776[/tex]

[tex] V^{2} = 113.0785[/tex]

Taking the square root, we have;

V = 10.6 m/s

Therefore, the final velocity of the object is 10.6m/s.

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