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One particle has a charge of 4.2 x 10-9 C, while another particle has a charge
of 1.10 x 10-9 C. If the two particles are separated by 0.005 m, what is the
electromagnetic force between them? The equation for Coulomb's law is
Fe = k992, and the constant, k, equals 9.00 x 109 Nm2/C2.
A. 8.31 x 10-6N
B. 1.66 x 10-5 N
C. 1.85 10-13 N
D. 1.66 10-3 N

Respuesta :

Answer:

D

Explanation:

Answer:

The forces between the charges is [tex]1.66*10^{-3} N[/tex]

Explanation:

Data given:

First charge [tex]q_{1} =4.2*10^{-9} C[/tex]

Another charge [tex]q_{2} =1.1*10^{-9} C[/tex]

Distance (r)= (0.005)m

Force(F)=?

It is based on Electrostatic force between two charges i.e. defined by Coulomb's law.

What is electrostatic force?

The force acting between two static charges, is called electrostatic force.

What is Coulomb's law?

The force acting between two charges is

(a) directly proportional to the product of charges F ∝ [tex]q_{1} q_{2}[/tex]

(b) inversely proportional to the square of the separation. F ∝ [tex]\frac{1}{r^{2} }[/tex]

From above;

[tex]F=k.\frac{q_{1} q_{2} }{r^{2} }[/tex]

On putting values: -

[tex]F=1.66*10^{-3} N[/tex]

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