Answer:
1. Initial vertical velocity its 0m/s
2. 2.47 seconds
3. 10.12 m/s
4.10.12 m/s
Explanation:
Remember that we have here two parts of a problem, first we know that the ball made a free fall of 30 meters, since the ball was hit horizontally and doesn't state otherwise the vertical velocity is 0. To calculate the time we just use 30 m as our Height and use the formula for vertical distance on free fall:
[tex]H=\frac{g*t^{2} }{2} \\[/tex]
Now we just solve for time:
[tex]t=\sqrt{\frac{2H}{g} }[/tex]
With this we just insert the values we know:
[tex]t=\sqrt{\frac{2H}{g} }\\t=\sqrt{\frac{2*30}{9.81} }\\t=2.47[/tex]
Now we know that the ball was 2.47 seconds in the air, so the ball hti the ground at the second 2.47.
To calculate the velocity of the ball we just need to divide the horizontal distance covered by the time it spent on air:
[tex]v=\frac{d}{t} \\v=\frac{25}{2.47} \\v=10.12[/tex]
The final and initial horizontal velocity of the ball would be the same since nothing states otherwise, of course the hitting of the ground would decrease its velocity but since nothing is said in the problem it is not considered.
1. The initial-vertical velocity of the golf ball is equal to zero because the ball would start its motion from a stationary position (at rest).
2. The time it took the golf ball to hit the ground is 2.47 seconds.
3. The initial-horizontal velocity of the golf ball is 10.12 m/s.
4. The final-horizontal velocity of the golf ball is 10.12 m/s.
Given the following data:
1. The initial-vertical velocity of the golf ball is equal to zero because the ball would start its motion from a stationary position (at rest).
2. To determine the time it took the golf ball to hit the ground:
At maximum height, time is given by the formula:
[tex]Time = \sqrt{\frac{2H}{g} }[/tex]
Where:
Substituting the given parameters into the formula, we have;
[tex]Time = \sqrt{\frac{2\times 30}{9.8} }\\\\Time = \sqrt{\frac{60}{9.8} }\\\\Time =\sqrt{6.12}[/tex]
Time = 2.47 seconds.
3. To determine the initial-horizontal velocity of the golf ball:
[tex]Horizontal\;velocity = \frac{Horizontal\;distance}{Time} \\\\Horizontal\;velocity = \frac{25}{2.47}[/tex]
Initial horizontal velocity = 10.12 m/s.
4. To determine the final-horizontal velocity of the golf ball:
The initial-horizontal velocity and final-horizontal velocity of the golf ball would be the same.
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