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Find the values of the ratios (red to blue) of the perimeters and areas of the similar figures. Write the ratios as fractions in simplest form.

Find the values of the ratios red to blue of the perimeters and areas of the similar figures Write the ratios as fractions in simplest form class=

Respuesta :

Answer: The ratio of the perimeter = 7/4

               The ratio of the area = 28/21

Took me alot of time ;p pls mark as brainliest! :)

The values of the ratios of the perimeters and areas of the red figure to the blue figure, which are similar figures, in the simplest form are:

Ratio of their perimeters:  [tex]\mathbf{\frac{4}{7}}[/tex]

Ratio of their areas: [tex]\mathbf{\frac{16}{49}}[/tex]

Recall:

  • The ratio of the perimeter of similar figures = a side length of one figure / corresponding side length of the other figure
  • The ratio of the areas of two similar figures = square of a length of one figure / square of a corresponding length of the other

Thus:

Side length of Red figure = 4

Side length of Blue figure = 7

Therefore:

The ratio of their perimeter = Side length of red figure / Side length of blue figure

  • Ratio of the perimeter of red figure to blue figure = [tex]\mathbf{\frac{4}{7}}[/tex]

The ratio of their areas = Side length of red figure / Side length of blue figure

  • Ratio of the perimeters of red figure to blue figure = [tex]\frac{4^2}{7^2}[/tex]

[tex]\mathbf{= \frac{16}{49}}[/tex]

In summary, the values of the ratios of the perimeters and areas of the red figure to the blue figure, which are similar figures, in the simplest form are:

Ratio of their perimeters:  [tex]\mathbf{\frac{4}{7}}[/tex]

Ratio of their areas: [tex]\mathbf{\frac{16}{49}}[/tex]

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