contestada

g Katie(50 kg) tries the water slide at the county fair. The starting point is 10.0 m above the ground. She starts from the top of the slide at rest. Assuming zero frictional lost, how fast will Katie be traveling at the bottom

Respuesta :

cjrodriguez89

Answer:

v= 14 m/s

Explanation:

  • Assuming no friction losses, the total mechanical energy must be conserved.
  • At the top of the slide, all the energy is gravitational potential energy, as she starts at rest.
  • At the bottom of the slide, if we choose this level as our zero reference level for the gravitational potential energy, all the energy will be purely kinetic.
  • So, we can write the following equality:
  • [tex]\Delta K + \Delta U =0[/tex]

        ⇒ΔK = -ΔU

        ⇒ [tex](\frac{1}{2}*m*v^{2}-0) =-(0- m*g*h) = m*g*h[/tex]

  • Rearranging terms and simplifying we can solve for v, as follows:

       [tex]v_{f} = \sqrt{2*g*h} =\sqrt{2*9.8m/s2*10.0m} = 14 m/s[/tex]

  • Katie's speed at the bottom of the slide will be 14 m/s.

Otras preguntas