Answer:
The angular speed of the Earth is approximately [tex]7.292\times 10^{-5}[/tex] radians per second.
Explanation:
We suppose that Earth rotates at constant angular speed. From Rigid Body Physics, we remember that angular speed of the planet ([tex]\omega[/tex]), measured in radians per second, is:
[tex]\omega = \frac{2\pi}{T}[/tex] (Eq. 1)
Where [tex]T[/tex] is the period, measured in seconds.
Therefore, the angular speed of the planet is:
[tex]\omega = \frac{2\pi}{23\,h\times \frac{3600\,s}{1\,h}+56\,min\times 60\,\frac{s}{min}+4\,s }[/tex]
[tex]\omega \approx 7.292\times 10^{-5}\,\frac{rad}{s}[/tex]
The angular speed of the Earth is approximately [tex]7.292\times 10^{-5}[/tex] radians per second.
