Answer:
13.62 g of urea
Explanation:
mass of water = 48.5 g
number of moles of water = 48.5 g/18g/mol = 2.7 moles of water
mole fraction of urea = 7.60×10−2
but mole fraction = mole of substance/ total number of moles
Let the number of moles of urea be x
7.60×10−2 =x/2.7 + x
7.60×10−2(2.7 +x) = x
0.21 + 0.076x = x
0.21 = x-0.076 x
0.21 = 0.924x
x = 0.21/0.924
x = 0.227 moles of urea
mass of urea in solution = number of mole * molar mass
= 0.227 moles * 60 g/mol = 13.62 g of urea
