The question is incomplete, the complete question is;
Solid phosphorus and chlorine gas react to form solid phosphorus pentachloride. Suppose you have 9.0 mol of P and 2.0 of Cl2 in a reactor. Calculate the largest amount of PCl5 that could be produced. Round your answer to the nearest 0.1 mol.
Answer:
0.8 mols
Explanation:
The equation of the reaction is:
P4(s)+10Cl2(g)→4PCl5(g)
We have to determine the limiting reactant by considering the reactant that yields the least number of moles of product.
1 mole of P yields 4 moles of PCl5
then 9.0 moles of P yields 9.0 * 4/ 1 = 36 moles of PCl5
Secondly;
10 moles of chlorine gas yields 4 moles of PCl5
2 moles of chlorine gas yields 2 *4/10 = 0.8 moles of PCl5
Since chlorine gas is the limiting reactant, the largest amount of PCl5 that can be produced in the reactor is 0.8 mols
The largest amount of PCl₅ that can be produced from the reaction is 0.8 mole
We'll begin by determining the limiting reactant.
P₄ + 10Cl₂ —> 4PCl₅
1 : 10
9 : 2
From the above, Cl₂ is the limiting reactant as little amount is available for the reaction.
From the balanced equation above,
10 moles of Cl₂ reacted to produce 4 moles of PCl₅.
Therefore,
2 moles of Cl₂ will react to produce = (2 × 4)/10 = 0.8 mole of PCl₅.
Thus, the largest amount of PCl₅ produced from the reaction is 0.8 mole
Compete Question
Solid phosphorus and chlorine gas react to form solid phosphorus pentachloride. Suppose you have 9.0 mol of P and 2.0 of Cl2 in a reactor. Calculate the largest amount of PCl5 that could be produced. Round your answer to the nearest 0.1 mol.
Learn more: https://brainly.com/question/14398319
