Answer:
The atomic mass of element X is 6.941 amu.
Explanation:
The atomic mass of the element X is given by:
[tex] m_{X} = \%_{X-6}m_{X-6} + \%_{X-7}m_{X-7} [/tex]
We have that the abundance of X-7 is 92.5%, so the abundance of X-6 is:
[tex] 100\% = \%_{X-6} + \%_{X-7} [/tex]
[tex] \%_{X-6} = 100\% - 92.5\% [/tex]
[tex] \%_{X-6} = 7.5\% [/tex]
Hence, the atomic mass of element X is:
[tex] m_{X} = \%_{X-6}m_{X-6} + \%_{X-7}m_{X-7} [/tex]
[tex] m_{X} = 0.075*6.015 amu + 0.925*7.016 amu = 6.941 amu [/tex]
Therefore, the atomic mass of element X is 6.941 amu.
I hope it helps you!
The atomic mass of element X is 6.941 amu.
[tex]m_x=\%x-6m_ X-6+\%x-7m_ X-7[/tex].....(1)
[tex]100\%=\%x-6+\%x-7\\\\%x-6\\\\=100\% - 92.5\%\\=7.5\%[/tex]
So, the atomic mass of element X from equation (1) is as follows :-
[tex]m_x=0.075\times6.015\ amu+0.925\times7.016\ amu\\\\=6.941\ amu[/tex]
The atomic mass of element X is 6.941 amu.
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