Answer:
The volume required is [tex]V = 11.91 \ liters [/tex]
Explanation:
From the question we are told that
The cars mileage is v = 28.0 mi/gal
The distance is d = 142 km
Converting the distance from km to miles
[tex]d = 142 * 0.6214 = 88.24 \ miles[/tex]
Generally the volume of gasoline needed is mathematically represented as
[tex]V = \frac{d}{ v}[/tex]
=> [tex]V = \frac{88.24}{ 28.0 }[/tex]
=> [tex]V = 3.151 \ gal[/tex]
Converting to Liters
=> [tex]V = 3.151 * 3.78 [/tex]
=> [tex]V = 11.91 \ liters [/tex]
