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Answer:

2.26 s

Explanation:

The following data were obtained from the question:

Height (h) = 25 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =..?

The time taken for the egg to hit the floor can be obtained as illustrated below:

h = ½gt²

25 = ½ × 9.8 × t²

25 = 4.9 × t²

Divide both side by 4.9

t² = 25 / 4.9

Take the square root of both side

t = √(25 / 4.9)

t = 2.26 s

Thus, it will take 2.26 s for the egg to hit the floor.

The time it takes an egg to hit the floor is required.

Time taken by the egg to hit the floor is 2.26 seconds.

y = Vertical displacement = 25 m

[tex]a_y[/tex] = g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

[tex]u_y[/tex] = Initial vertical velocity = 0

t = Time

From the kinematic equations of motion we have

[tex]y=u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow 25=0t+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{25\times 2}{9.81}}\\\Rightarrow t=2.26\ \text{s}[/tex]

Time taken by the egg to hit the floor is 2.26 seconds.

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