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Question 4

A coil of wire of 10 turns has across sectional area of 0.08 m2

. What is the total magnetic flux through

the coil if a magnetic field of 0.4T passes through the coil;

(a) perpendicular to the plane of the coil.

(b) at 20oto the plane of the coil

(c) by what percentage has the answer in (b) differed from the one in (a)? ​

Respuesta :

pfellas
a) flux = B A N = 0.4 x 0.08 x 10 = 0.32 Tesla

b) at 20 degrees = 0.32 Sin (20) = 0.32 x 0.34 = 0.11 Tesla

c) difference = 0.32 - 0.11 = 0.21 so
percentage = (0.21 / 0.32) x 100 = 66%

(a) The magnetic flux when the magnetic field is perpendicular to the plane is 0.32 Wb

(b) The magnetic flux when the magnetic field is at 20° to the plane is 0.30 Wb

(c) the percentage difference between the answers is 6.25%

Magnetic Flux:

Number of turns of the coil, N = 10

Cross-sectional area, A = 0.08 m²

the magnetic field through the coil, B = 0.4 T

(a) the magnetic field is perpendicular to the plane of the coil

magnetic flux Ф = NABcosθ

here θ = 0°, since the area vector is also perpendicular to the plan of the coil.

Ф = 10×0.08×0.4×1 Wb

Ф = 0.32 Wb

(b)  the magnetic field is at 20° to the plane of the coil

Ф = NABcosθ

Ф = 10×0.08×0.4×cos20

Ф = 0.30 Wb

(c) The difference in the results is:

ΔФ = 0.32-0.30 = 0.02 Wb

percentage dfference:

ΔФ = (0.02/0.32) × 100

ΔФ = 6.25 %

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