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Student A is 15 years old. Student B is one-third older. How many years ago was student B
twice as old as student A?
A) 5
B) 7
C) 9
D) 10

Respuesta :

Answer:

D

Step-by-step explanation:

one third of 15 is 5

15 + 5 = 20

Student B is 20 years old, 5 years older than student A

10 years ago, Student B was 10 and Student A was 5.

The number of years ago was student B twice as old as student A should be 10 when the student A age is given.

Calculation of the number of years:

Since

Student A is 15 years old. Student B is one-third older

One-third of 15 should be 5

So, total be like

= 15 + 5

= 20

So, the number of years  be like

= 20 - 10

= 10

hence, The number of years ago was student B twice as old as student A should be 10.

learn more about age here: https://brainly.com/question/10189250

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