A concentrated cleaning solution must be mixed with water in a container that allows users to spray onto the surfaces they need to clean. Pam’s mom asked her to add 30 ounces of cleaning concentrate into the sprayer and then add water to fill the sprayer. Her father told her that the sprayer must contain 20% cleaning concentrate and 80% water.

a. How many ounces does the sprayer hold?
ounces

b. How much water was added to the sprayer?
ounces

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facundo3141592 facundo3141592 · Answer 1 · 2020-10-29T01:33:55+01:00

Answer: The sprayer can hold 150 ounces, and Pam needs to add 120 ounces of water.

Step-by-step explanation:

The data that we know is:

We must use 30 oz of cleaning concentrate.

The end product must be 80% water and 20% cleaning concentrate.

This means that:

Mass of water/total mass in the sprayer = 0.8

mass of cleaning concentrate/total mass in the sprayer = 0.2

Then, let's define the variables:

X = ounces that the sprayer can hold.

Y = ounces of water added.

Then we have the equations:

30oz + X = Y.

30oz/Y = 0.20

X/Y = 0.80

From the second equation we can find the value of Y.

30oz = 0.20*Y

30oz/0.20 = Y = 150oz.

Then the sprayer can hold 150 ounces.

Now from the third equation we have:

X/Y = 0.8

We know that Y = 150oz

Then:

X/150oz = 0.8

X = 0.8*150oz = 120 oz.

Then the water that must be added is 120 ounces.