Answer:
+-1, +-2,+-5, +-10
Step-by-step explanation:
you first find all the numbers that can go into the constant which is 10, so negative and positive 1 can go into 10, negative and positive 2 can go into 10 etc.
The possible rational roots of the polynomial equation
[tex]1,-1} , +\frac{1}{2} , -\frac{1}{2} , +2,-2, +5,-5, +\frac{5}{2} ,-\frac{5}{2} ,+10,-10[/tex]
Given :
The polynomial equation is
[tex]2x^{9}-3x^{7}+11x+10=0[/tex]
To find out possible rational roots, we use rational root theorem
Rational root of the form
[tex]\frac{p}{q}[/tex] where p is the constant and q is the leading coefficient
p=10 and q=2
Lets write all the factors of 10 and 2
Factors of 10 are 1,2,5,10
factor of 2 are 1,2
Rational root of the form
[tex]+- factors of \frac{p}{q} =+-\frac{1,2,5,10}{1,2}[/tex]
We consider both positive and negative factors. Ignore the repeated roots
So possible rational roots are
[tex]1,-1} , +\frac{1}{2} , -\frac{1}{2} , +2,-2, +5,-5, +\frac{5}{2} ,-\frac{5}{2} ,+10,-10[/tex]
Learn more : brainly.com/question/13211306
