Two cards are randomly drawn. What is the probability of drawing two blue cards if the first card is not included in the second draw? Simplify your answer completely. [?] Enter the number that [] belongs in the green box Hint: Multiply the probability of the 1st Event by the probability of the 2nd Event to get your answer​

Respuesta :

Using it's concept, it is found that the probability of drawing two blue cards is of [tex]p = \frac{5}{14}[/tex].

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

Researching this problem on the internet, it is found that out of 8 cards, 5 are blue, hence:

  • The probability of the first card being blue is 5/8.
  • If the first is blue and not replaced, the probability of the second card being blue is 4/7.

Hence, the probability of both cards being blue, which is what the questions asks, is:

[tex]p = \frac{5}{8} \times \frac{4}{7} = \frac{5}{14}[/tex]

More can be learned about probabilities at https://brainly.com/question/14398287

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