Answer:
45
Explanation:
[tex]m_1[/tex] = First sample mass of water = [tex]75\ \text{g}[/tex]
[tex]\Delta T_1[/tex] = Change in temperature of the first sample of water = [tex]25-T[/tex]
[tex]m_2[/tex] = First sample mass of water = [tex]100\ \text{g}[/tex]
[tex]\Delta T_1[/tex] = Change in temperature of the first sample of water = [tex]T-60[/tex]
[tex]T[/tex] = Final temperature of the mixture
[tex]c[/tex] = Specific heat of water
Heat lost by water will be equal to the heat gained so we get
[tex]m_1c\Delta T_1=m_2c\Delta T_2\\\Rightarrow 75(25-T)=100(T-60)\\\Rightarrow 0.75(25-T)=T-60\\\Rightarrow 18.75-0.75T=T-60\\\Rightarrow 18.75+60=T+0.75T\\\Rightarrow 78.75=1.75T\\\Rightarrow T=\dfrac{78.75}{1.75}\\\Rightarrow T=45\ ^{\circ}\text{C}[/tex]
The final temperature of the water is 45.
