The speed of the Jaguar before it began to skid : 32.532 m/s
Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration
An equation of uniformly accelerated motion
[tex]\large {\boxed {\bold {x=xo+vo.t+\frac {1} {2} at ^ 2}}}[/tex]
vt = vo + at
vt² = vo² + 2a (x-xo)
x = distance on t
vo / vi = initial speed
vt / vf = speed on t / final speed
a = acceleration
[tex]\tt v_f=v_i-at\rightarrow v_f=0(stop),a-=deceleration\\\\0=v_i-2.2.t\\\\v_i=2.2t\\\\x=v_i.t-\dfrac{1}{2}at^2\\\\x=2.2.t^2-\dfrac{1}{2}at^2\\\\320=2.2t^2-\dfrac{1}{2}2.2t^2\\\\320=2.2t^2-1.1t^2\\\\320=1.1t^2\Rightarrowt=17.06~s\\\\v_i=2.2\times 17.06\\\\v_i=37.532~m/s[/tex]
