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In the diagram below, lines AB, CD, and EF all intersect at the common point E. If CD bisects angle AGF and angle AGD=68° then what is the measure of angle BGF ? Explain how you arrived at your answer.​

In the diagram below lines AB CD and EF all intersect at the common point E If CD bisects angle AGF and angle AGD68 then what is the measure of angle BGF Expla class=

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akposevictor

Answer:

m<BGF = 44°

Step-by-step explanation:

Since line CD bisects angle AGF, it implies that the measure of angle AGF is twice the measure of angle AGD.

m<AGD = 68°, therefore,

m<AGF = 2*AGD

m<AGF = 2*68°

m<AGF = 136°

m<AGF + m<BGF = 180° (linear pair)

136° + m<BGF = 180° (Substitution)

Subtract 136° from each side

m<BGF = 180° - 136°

m<BGF = 44°

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