Respuesta :
Answer:
The treasure is 0.8 inches from the south edge on Ali's map.
Step-by-step explanation:
Scaling factor, f = (Original length)/(Scalet length)...(i)
Let [tex]f_1[/tex] and [tex]f_2[/tex] be the scaling factors used by Ali and Kiana respectively.
Given that the field is 400 feet= 400x12 inches wide and Ali made an 8-inch-wide map to record its location.
So, [tex]f_1 = (400\times12)/8=600[/tex]...(ii)
Kiana made her map using a scale of 1-inch to 20 feet=20x12 inches.
So, [tex]f_2=(20\times12)/1=240[/tex]...(iii)
As on Kiana's map, the treasure is 2 inches from the south edge of the field,
so, from equations (i), and (ii), the original length of the treasure for the south edge of the field
[tex]=2\times f_2[/tex]
=2x240
=480 inches
Now, again from the equation (i) and (ii), the scaled length of the treasure on Ali's map
= 480/f_1
=480/600
=0.8 inches
Hence, the treasure is 0.8 inches from the south edge on Ali's map.