Step-by-step explanation:
Hey there!
The equation of a line passes through point (-2,2) is;
(y-2) = m1(X+2).............(i)
Another equation is;
y= 2/3x +2............ (ii)
From equation (ii)
y = 2/3x+2
Comparing the equation with y= mx+c, we get;
Slope(M2) = 2/3.
For perpendicular lines the condition is; M1*M2= -1
So, let's find M1 here.
[tex]m1 \times \frac{2}{3} = - 1 [/tex]
[tex]2m1 = - 3[/tex]
[tex]m1 = \frac{ - 3}{2} [/tex]
Therefore, M1= -3/2.
Putting the value of M1 in equation (i), we get;
[tex](y - 2) = - \frac{3}{2} (x + 2)[/tex]
[tex](y - 2) = - \frac{3}{2} x + 2 \times - \frac{3}{2} [/tex]
[tex](y - 2) = - \frac{3}{2} x - 3[/tex]
[tex]y = - \frac{3}{2} x - 1[/tex]
Therefore, the equation is y= -3/2x-1.
Hope it helps...
