[tex]47 = 2(x + 3) + 3(x - 3)[/tex]
[tex]47 = 2x + 6 + 3x + - 9[/tex]
[tex]47 =(2 x + 3x) + (6 + - 9)[/tex]
[tex]47 = 5x + - 3[/tex]
[tex]47 = 5x - 3[/tex]
[tex]5x - 3 = 47[/tex]
[tex]5x = 47 + 3[/tex]
[tex]5x = 50[/tex]
[tex]x = \frac{50}{10} [/tex]
[tex]x = 10[/tex]
Let us check whether or not we have found out the correct value of x by placing 10 in the place of x .
So :-
[tex]47 = 2(10 + 3) + 3(10 - 3)[/tex]
[tex]47 = (20 + 6) + (30 - 9)[/tex]
[tex]47 = 26 + 21[/tex]
[tex]47 = 47[/tex]
LHS = RHS
As the left hand side of the equation is equal to the right hand side of the equation , we have found out the correct value of x .
Therefore , 47 = 2 ( 10 + 3 ) + 3 ( 10 - 3 ) and x = 10 .
