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Answer:

[tex]y=-2^{(x+2)}+1[/tex]

Step-by-step explanation:

Equation of the parent function of the graph attached is,

y = [tex]2^{x}[/tex]

Let the equation of the transformed function function shown in the graph be,

y = a(2ˣ) + b

Now we will find the values of a and b by substituting the points lying on the curve.

For (-2, 0),

0 = a(2⁻²) + b

[tex]\frac{a}{4}+b=0[/tex] ------(1)

For (0, -3),

-3 = a(2⁰) + b

a + b = -3 --------(2)

Subtract equation (1) from equation (2),

(a + b) - ([tex]\frac{a}{4}+b[/tex]) = 0 + 3

[tex]\frac{3a}{4}=3[/tex]

a = -4

From equation (2),

-4 + b = -3

b = 1

Therefore, equation of the transformed function will be,

[tex]y=-4(2^x)+1[/tex]

[tex]y=-2^{2}(2^x)+1[/tex]

[tex]y=-2^{(x+2)}+1[/tex]

Graph transformation is the process by which an existing graph is modified to produce a variation of the proceeding graph.

Equation of transformed graph is, [tex]y=-2^{x+2}+1[/tex]

Here,  equation of original graph is given, [tex]y=2^{x}[/tex]

Let us consider, equation of transformed graph is,  [tex]y=m(2^{x} )+n[/tex]

Since, given graph passing through points (-2,0) and (0,-3)

Substituting above points into equation.

We get two equation,

                                      m +4n = 0

                                     m + n = -3

After solving, we get   m= -4 and  n = 1

So, equation becomes  [tex]y=-2^{x+2}+1[/tex]

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