Respuesta :
Answer:
30.854%
Step-by-step explanation:
First, we find the z-score corresponding to the value given
z-score = (x - mean)/SD
Z-score = (36-35)/2 = 1/2 = 0.5
we find the Probability of (x > 0.5)
we use the standard normal distribution table for this
P( x > 0.5) = 0.30854
This has a percentage 30.854%
Answer:
30.854%
Step-by-step explanation:
Hope this helps!